A man of mass 60 kg is standing on a weighing machine kept in a box of mass 30 kg as shown in figureA man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If he manages to keep the box at rest (i) what is the weight shown by the machine ?5. There are two forces on the 2 kg box in the overhead view of the figure below but only one is shown. The figure also shows the acceleration of the box. Find the second force (a) in unit-vector notation and as (b) magnitude and (c) direction. 33 180 33 213 32 20.78 32 21 38.27 tan ( 32ˆ 20.78ˆ) 20.78 12 20 32A man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If he manages to keep the box at rest (i) what is the weight shown by the machine ?figure (5-E.21) shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling by a light rope, the other end of which is held by the man himself.An elevator filled with passengers has a mass of. 1.70 × 10 3 kg. 1.70 × 10 3 kg. (a) The elevator accelerates upward from rest at a rate of. 1.20 m/s 2. 1.20 m/s 2 for 1.50 s. Calculate the tension in the cable supporting the elevator. (b) The elevator continues upward at constant velocity for 8.50 s.A 50-kg person stands 1.5 m away from one end of a uniform 6.0-m-long scaffold of mass 70.0 kg. Find the tensions in the two vertical ropes supporting the scaffold. Check Your Understanding 12.8 Question 13: The elevator shown in figure (below) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B? Solution: From the free body diagram, The apparent weight of the box = 0.5 x 10-2x0.5 = 4NAir is at 30 o C and 115 kPa at the beginning of the isothermal compression process during which 155 kJ/kg of heat is rejected. Heat transfer to air occurs at 1250 K. Determine (a) the maximum pressure in the cycle, (b) the net work output per unit mass of air and (c) the thermal efficiency of the cycle. A person is standing on a weighing machine placed on the floor of an elevator. The elevator starts going up with some acceleration, moves with uniform velocity for a while and finally decelerates to stop. The maximum and the minimum weights recorded are 72 k g and 60 k g.6. Figure shows a man of mass 50 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If the man manages to keep the box at rest, the weight shown by the machine is A) 50 N B) 100 N C) 150 N D) 200 N 2But we'll keep it simple. Oh, let me be clear. He doesn't weigh 10 kilograms. That's wrong. He has a mass of 10 kilograms. Weight is the force due to gravity. Mass of the amount of stuff, the amount of matter there is. Although I that's not a rigorous definition. So the mass of the individual, of this toddler sitting in the elevator, is 10 ...A man raises a box of mass 50kg to a height of 2m in 20s, while another man raises the same box to the same height in 50s. (a) Compare: (i) the work done, and (ii) the power developed by them. (b) Calculated: (i) the work done, and (ii) the power developed by each man. Take g = 10N kg-1.A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a radius of 0.25m. ... The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is standing three meters away from the center. ... each weighing 45kg. They both sit on ...Question From - Cengage BM Sharma MECHANICS 1 NEWTON'S LAWS OF MOTION 1 JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TE...Mar 25, 2014 · I’d say, on average, somewhere between 30-120 minutes depending on the specifics (goals, rep ranges, rest periods, type of training split, total volume, overall training approach, 100 other factors, etc. etc. etc.). Narrowing that down even further, you’ll probably be looking at something like 45-90 minutes most of the time, especially with ... Question 13: The elevator shown in figure (below) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B? Solution: From the free body diagram, The apparent weight of the box = 0.5 x 10-2x0.5 = 4NA team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the loaded sled with its rider has a mass of 210 kg. (a) Calculate the acceleration of the dogs starting from rest if each dog exerts an average force of 185 N backward on the snow. Jan 13, 2020 · The formula for BMI was devised in the 1830s by Belgian mathematician Adolphe Quetelet and is universally expressed in kg/m 2. Body mass index is a measure of body fat and is commonly used within the health industry to determine whether your weight is healthy. (electron mass = 9.11× 10-31 kg, proton mass = 1.67×10-27 kg, 1 eV = 1.60 ×10-19 J). Question 6.13 A rain drop of radius 2 mm falls from a height of 500 m above the ground. It falls with decreasing acceleration (due to viscous resistance of the air) until at half its original height, it attains its maximum (terminal) speed, and moves ...kda mining poolbmw e30 m3 for sale near frankfurtwillow court apartments failsworth Figure shows a man of mass 50kg standing on a light weighing machine kept in a box of mass 30kg. The box is hanging from a pulley fixed to the ceillin asked Sep 12, 2020 in Physics by JayantChakraborty ( 78.8k points)Question From – Cengage BM Sharma MECHANICS 1 NEWTON'S LAWS OF MOTION 1 JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TE... Dec 10, 2020 · Figure (5−E21) shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling by a light rope, the other end of which is held by the man himself. a larger mass.] Explain your reasoning. 40 4. In Figure 4 below, a graph shows the relationship between mass and volume for two substances, A and B. Use the graph to answer questions about these two substances. Two Pan Balance a) You have built a simple two-pan balance shown above to compare the masses of substances A and B. What In this Physics video lecture on 'H C Verma Solutions' for class 11, IIT JEE in Hindi we solved a problem on 'Newton's Laws of Motion' ( chapter 5 ) from the...1) An object of 100 Kg mass is kept on an elevator surface. The elevator is moving with a constant velocity of 3 meter per second. What is the normal reaction on the object in Newton? 2) A 40 Kg boy is moving upwards in a lift with an acceleration of 2 meters /second^2. What would be the weight felt by him, if measured on a scale?that its center of mass is at its geometric center. Since the bar is 1.0 m long, the x cm is at 0.5 m. So we have a downward force of F = m g = 6 kg(10 m/s2) = 60 N at 0.5 m away from the pivot point. To balance this out we need c = cc (clockwise and counter-clockwise) r F = r F r (40 N) = (0.5 m) (60 N) 40 r = 30 r = 0.75 mIn the pulley system shown in the figure below, a m = 14.0-kg mass is released from rest and falls, causing the uniform M = 12.5-kg cylinder of diameter 27.0 cm to turn about a friction-less axle t...mass is 68 kg. (That is his mass if he weighs 150 lb when standing on the surface.) The distance between him and the surface of the Earth is (6371 + 200) km (his altitude + the Earth's radius) = 6.57 x10 6 meters. Plug that into the formula for the gravitational force and you get F = 142 lbs. On Earth he weighed 150 lbs.FigurE 5.2 (a) Engine, chains, and ring T 1 T 3 T 2 O 60° (b) Free-body diagram for engine (c) Free-body diagram for ring O As you probably expect, this force equals the gymnast's weight. The other forces on the rope are its own weight (magnitude 100 N) and the upward force (magnitude T 2) exerted on its upper end by the O-ring. The ...smtpclient sslprotocolsblender convert mesh to bezier curvehypixel housing parkour checkpoint Two blocks of mass 2 kg and 5 kg are connected by an ideal string passing over a pulley. The block of mass 2 kg is free to slide on a surface inclined at an angle of 30° with the horizontal whereas 5 kg block hangs freely. Find the acceleration of the system and the tension in the string.A person is standing on a weighing machine placed on the floor of an elevator. The elevator starts going up with some acceleration, moves with uniform velocity for a while and finally decelerates to stop. The maximum and the minimum weights recorded are 72 k g and 60 k g.t = I / Faverage = 12.75 kgm/s / +1000 = 0.013 s. The ball is in contact with the wall for approximately 13 milliseconds. 5. A ball of mass 0.25 kg glances of a wall as shown in the diagram. The ball approaches at 15 m/s at θ = 30° and leaves at 12 m/s at φ = 20°. In the system below, blocks of masses m 1 = 10 Kg and m 2 = 30 Kg are linked by a massless string through a frictionless pulley. a) Find the magnitude of the acceleration of the two masses if the coefficient of kinetic friction between the inclined plane and mass m 1 is equal to 0.4. b) Find the magnitude of the tension in the string.A 50.0-kg crate rests on the bed of a truck as shown in Figure 6.18. The coefficients of friction between the surfaces are μ k = 0.300 μ k = 0.300 and μ s = 0.400 . μ s = 0.400 . Find the frictional force on the crate when the truck is accelerating forward relative to the ground at (a) 2.00 m/s 2 , and (b) 5.00 m/s 2 .A person of mass m = 75 kg is standing on it. The mass of the ladder is M = 10 kg. The coefficient of static friction between the ground and ladder is μ s1 = 0.5, and the coefficient of static friction between the wall and ladder is μ s2 = 0.3. What is the minimum angle θ so that the ladder doesn't slip? Hint and answer Problem # 5 Two ...Write down the Newton's 2nd law (net force mass* acceleration) for each mass. Calculate the acceleration of the entire system. Calculate the tension in the string. 8. A book weighing 5 kg is resting on a table. The coefficient of friction between the book and the table is 0.4. If one applies a force F to push the book as shown then theA man of mass `60kg` is standing on a weighing machine kept in a box of mass `30kg` as shown in the diagram If the man man ages to keep the box stationary, f... 6. Figure shows a man of mass 50 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If the man manages to keep the box at rest, the weight shown by the machine is A) 50 N B) 100 N C) 150 N D) 200 N 2The mass of the crate hanging on the left side of the table is 0.820 kg and the mass of the crate on the table is 1.78 kg. If the coefficient of kinetic friction between the table and the 1.78 kg . physics. A mover pushes a 4.21 kg box with a 36.6 N constant horizontal force up a 10.0° ramp that has a height of 1.57 m.For example: Determine the force of gravity on a 68 kg person on the surface of the earth. The mass of the earth is 5.98 x 10 24 kg. Make sure all your variables have the proper units. m 1 = 5.98 x 10 24 kg, m 2 = 68 kg, G = 6.673 x 10-11 Nm 2 /kg 2, and d = 6.38 x 10 6 mQuestion 13: The elevator shown in figure (below) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B? Solution: From the free body diagram, The apparent weight of the box = 0.5 x 10-2x0.5 = 4N A small block of mass m 1 = 1.0 kg is put on the top of a large block of mass m 2 = 4.0 kg. The large block can move on a horizontal frictionless surface while the coefficients of friction between the large and small blocks are μ s = 0.60 and μ k = 0.4. A horizontal force F = 5.0 N is applied to the small block (See Figure 5). Find the ...Find the acceleration of the 500 g block in figure shown below. (Ans : 8g/13 downwards ) 8. Figure (5-E21) shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself.Sep 07, 2017 · 2) Gehan EA, George SL. Estimation of human body surface area from height and weight. Cancer Chemother Rep 1970;54:225-35. Equation: BSA (m 2) = 0.0235 x Height(cm) 0.42246 x Weight(kg) 0.5145 6 crystal shops in carytownjohn darko audiodownload video A man of mass 60kg standing on a light weighting machine kept ina box of mass 30kg. The box is hanging from a pulley fixed to the ceiling through a light rope , the other end of which is held by the man himself . If the manages to keep the box at rest (1) what is weight shown by the machine ?The first rope makes an angle of 30 ° with the ceiling, while the second rope makes an angle of 45 ° with the ceiling. Let's draw the free-body diagram of the sphere. 1) We sketch what is happening: Sketch of the sphere hanging from the two ropes attached to the ceiling. 30 ° 45 °.Ans. 2TKE = ½mv2 = ½(2.50 kg)(4.53 m/s) = 25.66 J Gravitational Potential Energy GPE = mg h 12. A 5.0 kg mass is initially sitting on the floor when it is lifted onto a table 1.15 meters high at a constant speed. a. How much work will be done in lifting this mass onto the table? Ans. W = F d = m g d = 5.0 kg .Jan 13, 2022 · The airplane has a mass m0 and travels at velocity V0. An external force F to the airplane shown above moves it to point “1”. The airplane’s new location is X1 and time t1. The mass and velocity of the airplane change during the flight to values m1 and V1. A tractor of mass 950 kg is used to lift gravel weighing 4 kN. Determine the reaction at each of the two (a) rear wheels A, (b) ... 0 2 75 1 60 0 15 250 0 3 250 0: ( )( ) ( )( . ) ... each of mass 350 kg, are placed as shown in the bed . of a 1400-kg pickup truck. Determine the reactions at each ofA block of mass 1.75 kg is pushed up against a wall by a force P~that makes an angle of = 50:0 angle with the horizontal as shown below. The coe cient of static friction between the block and the wall is 0.260. • a) Determine the possible values for the magnitude of jP~jthat allow the block to remain stationary. (If there is no maximum,Air is at 30 o C and 115 kPa at the beginning of the isothermal compression process during which 155 kJ/kg of heat is rejected. Heat transfer to air occurs at 1250 K. Determine (a) the maximum pressure in the cycle, (b) the net work output per unit mass of air and (c) the thermal efficiency of the cycle. 3 A slab ofmarble (density 2.7 x 103 kg/m") has a mass of 10 kg. What is its volume? 4 A piece of plate glass has dimensions 30 em x 40 em and a mass of 700 g. Taking thedensity ofglass as 2.5 g/cm3 , calculate the thickness ofthe glass. 5 A flask was weighed with a bung and clip and found to have a mass of 185.00 g.5. There are two forces on the 2 kg box in the overhead view of the figure below but only one is shown. The figure also shows the acceleration of the box. Find the second force (a) in unit-vector notation and as (b) magnitude and (c) direction. 33 180 33 213 32 20.78 32 21 38.27 tan ( 32ˆ 20.78ˆ) 20.78 12 20 32In figure shows a man of mass 60 kg standing on a light In figure shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself.For a mass m= kg, the elevator must support its weight = mg = Newtons to hold it up at rest. If the acceleration is a= m/s² then a net force= Newtons is required to accelerate the mass. This requires a support force of F= Newtons. Note that the support force is equal to the weight only if the acceleration is zero, and that if the acceleration is negative (downward), the support force is less ...A man of mass 60kg standing on a light weighting machine kept ina box of mass 30kg. The box is hanging from a pulley fixed to the ceiling through a light rope , the other end of which is held by the man himself . If the manages to keep the box at rest (1) what is weight shown by the machine ?wifi 6 antenna redditdyndns freeglock 21 gen 3 slide ebay A tractor of mass 950 kg is used to lift gravel weighing 4 kN. Determine the reaction at each of the two (a) rear wheels A, (b) ... 0 2 75 1 60 0 15 250 0 3 250 0: ( )( ) ( )( . ) ... each of mass 350 kg, are placed as shown in the bed . of a 1400-kg pickup truck. Determine the reactions at each ofA team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the loaded sled with its rider has a mass of 210 kg. (a) Calculate the acceleration of the dogs starting from rest if each dog exerts an average force of 185 N backward on the snow.4. A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force F , such that the block does not move downward ? (Take, g = 10ms−2) [JEE Main 2019, 9 Jan Shift-I] Fturns and walks 30. meters south to an art classroom. What is the girl's total displace-ment from the history classroom to the art classroom? ANSWER: (1) 20. m south 2. A projectile is ﬁred with an initial velocity of 120. meters per second at an angle, h, above the horizontal. If the projectile's initial hori-zontal speed is 55 meters ...kg to mg How to convert Milligrams to Kilograms. 1 milligram (mg) is equal to 1/1000000 kilograms (kg). 1 mg = (1/1000000) kg = 10-6 kg = 0.000001 kg. The mass m in kilograms (kg) is equal to the mass m in milligrams (mg) divided by 1000000: Sep 26, 2013 · BMI: 25.2. Height: 183.3 cm (72.2 inches) Waist: 91 cm (35.8 inches) A normal BMI ranges from 18.5 to 24.9. A BMI of 25 to 29.9 is considered overweight, and anything over 30 is obese , meaning ... Answer (1 of 5): Elevator Problem In the Given Question, As the Elevator cables breaks it is going to accelerate Downwards. therefore F (apparent weight or Resultant force on man) = W - mass x acceleration of the elevator F = Weight of the man - mass x 9.8 {as elevator is falling freely, its a...145. Figure shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If he manages to keep the box at rest (i) what is the weight shown by the machine ?A block of mass m= 3:20 kg is pushed a distance d = 4.60 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 26.0 below the horizontal as shown in the gure below. a) Determine the work done on the block by the applied force. b) Determine the work done on the block by the normal forceFigure shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling through a light rope, the other end of which is held by the man himself. If the man manages to keep the box at rest, what is the weight shown by the machine?1) An object of 100 Kg mass is kept on an elevator surface. The elevator is moving with a constant velocity of 3 meter per second. What is the normal reaction on the object in Newton? 2) A 40 Kg boy is moving upwards in a lift with an acceleration of 2 meters /second^2. What would be the weight felt by him, if measured on a scale?A bucket of mass 1.60 kg is whirled in a vertical circle of radius 1.30 m. At the lowest point of its motion the tension in the rope supporting the bucket is 25.0 N. (a) Find the speed of the bucket. Enter a number.1 m/s (b) How fast must the bucket move . physics. A 5.4-kg bucket of water is raised from a well by a rope.A block of mass m= 3:20 kg is pushed a distance d = 4.60 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 26.0 below the horizontal as shown in the gure below. a) Determine the work done on the block by the applied force. b) Determine the work done on the block by the normal forceDec 10, 2020 · Figure (5−E21) shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling by a light rope, the other end of which is held by the man himself. Force Newton kg-m/sec2 Work, energy & heat Joule N-m Moment of inertia kilogram metre sqare kg-m2 Power Watt J/s Systems of units: Generally we use four systems of units. Centimeter-gram-second (C.G.S) system: In this system the units of fundamental quantities i.e. mass, length and time are expressed in gram, centimeter and second respectively.A 90-kg man walks on a sawhorse, as shown below. The sawhorse is 2.0 m long and 1.0 m high, and its mass is 25.0 kg. Calculate the normal reaction force on each leg at the contact point with the floor when the man is 0.5 m from the far end of the sawhorse.The easiest way to calculate gravitational potential energy is to use our potential energy calculator. This tool estimates the potential energy on the basis of three values. These are: Gravitational acceleration, which on Earth amounts to 9,81 m/s². Then the calculator will give you the result in joules.A 90-kg man walks on a sawhorse, as shown below. The sawhorse is 2.0 m long and 1.0 m high, and its mass is 25.0 kg. Calculate the normal reaction force on each leg at the contact point with the floor when the man is 0.5 m from the far end of the sawhorse.Jun 14, 2020 · Figure shows a man of mass 50kg standing on a light weighing machine kept in a box of mass 30kg. The box is hanging from a pulley fixed to the ceillin asked Sep 12, 2020 in Physics by JayantChakraborty ( 78.8k points) character searchtwisted wonderland x ever after high wattpad But we'll keep it simple. Oh, let me be clear. He doesn't weigh 10 kilograms. That's wrong. He has a mass of 10 kilograms. Weight is the force due to gravity. Mass of the amount of stuff, the amount of matter there is. Although I that's not a rigorous definition. So the mass of the individual, of this toddler sitting in the elevator, is 10 ...A machine lifts a mass of weight 490.5 N through a height of 12 m when 7.85 kJ of energy is supplied to it. Determine the efficiency of the machine. Work done in lifting mass = force × distance moved = weight of body × distance moved = 490.5 N × 12 m = 5886 J = useful energy output . Energy input = 7.85 kJ = 7850 J . Efficiency, η = mcg/kg) ivermectin in a fasted state or 30 mg (333 to 600 mcg/kg) ivermectin following a standard high-fat (48.6 g of fat) meal. Administration of 30 mg ivermectin following a high-fat meal resulted in an approximate 2.5 fold increase in bioavailability relative to administration of 30 mg ivermectin in the fasted state. Microbiology FigurE 5.2 (a) Engine, chains, and ring T 1 T 3 T 2 O 60° (b) Free-body diagram for engine (c) Free-body diagram for ring O As you probably expect, this force equals the gymnast's weight. The other forces on the rope are its own weight (magnitude 100 N) and the upward force (magnitude T 2) exerted on its upper end by the O-ring. The ...Feb 03, 2022 · Formula: weight (kg) / [height (m)] 2. Or. [weight (kg) / height (cm) / height (cm)] x 10,000. With the metric system, the formula for BMI is weight in kilograms divided by height in meters squared. Since height is commonly measured in centimeters, an alternate calculation formula, dividing the weight in kilograms by the height in centimeters ... Brainly is the knowledge-sharing community where 350 million students and experts put their heads together to crack their toughest homework questions.The 5-kg mass below is moving with a constant speed of 4 m/s to the right. Use your understanding of force relationships and vector components to fill in the blanks in the following diagram and to determine the net force and acceleration of the object. In the following figure shows a man of mass 60 kg standing on a light weighing machine kept in a box of mass 30 kg. The box is hanging from a pulley fixed to the ceiling by a light rope, the other end of which is held by the man himself. If the man manages to keep the box at rest, what is the weight recorded on the machine?Question 13: The elevator shown in figure (below) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B? Solution: From the free body diagram, The apparent weight of the box = 0.5 x 10-2x0.5 = 4NA team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the loaded sled with its rider has a mass of 210 kg. (a) Calculate the acceleration of the dogs starting from rest if each dog exerts an average force of 185 N backward on the snow. Brainly is the knowledge-sharing community where 350 million students and experts put their heads together to crack their toughest homework questions.Answer (1 of 5): Elevator Problem In the Given Question, As the Elevator cables breaks it is going to accelerate Downwards. therefore F (apparent weight or Resultant force on man) = W - mass x acceleration of the elevator F = Weight of the man - mass x 9.8 {as elevator is falling freely, its a...Question 13: The elevator shown in figure (below) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B? Solution: From the free body diagram, The apparent weight of the box = 0.5 x 10-2x0.5 = 4NIn the pulley system shown in the figure below, a m = 14.0-kg mass is released from rest and falls, causing the uniform M = 12.5-kg cylinder of diameter 27.0 cm to turn about a friction-less axle t...Two blocks of mass 2 kg and 5 kg are connected by an ideal string passing over a pulley. The block of mass 2 kg is free to slide on a surface inclined at an angle of 30° with the horizontal whereas 5 kg block hangs freely. Find the acceleration of the system and the tension in the string.Jun 14, 2020 · Figure shows a man of mass 50kg standing on a light weighing machine kept in a box of mass 30kg. The box is hanging from a pulley fixed to the ceillin asked Sep 12, 2020 in Physics by JayantChakraborty ( 78.8k points) The door in the figure below has height c = 3.00 m , mass m = 8.30 kg , and center of gravity G, where b = 1.50 m and d = 1.50 m. If the man exerts a force F = 9.40 N at h = 1.00 m off the ground ...(Mass of the man = 65 kg.) Answer: Given acceleration of conveyor belt a = 1 m s-2 µ s = 0.2 mass of man m = 65 kg Then man experiences a pseudo force F s = ma as he is in an accelerating frame as shown in the figure. Hence to maintain his equilibrium he exerts a force F = - Fs = ma = 65 × 1 = 65 N in direction of motion of belt.A 90-kg man walks on a sawhorse, as shown below. The sawhorse is 2.0 m long and 1.0 m high, and its mass is 25.0 kg. Calculate the normal reaction force on each leg at the contact point with the floor when the man is 0.5 m from the far end of the sawhorse.rclpy rateboer goat breeders associationair bar box red bullgumtree sydney home and gardendbeaver dump database l3